N+3=(10-n)/3

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Solution for N+3=(10-n)/3 equation: 



+3=(10-N)/3

We move all terms to the left:

+3-((10-N)/3)=0

We add all the numbers together, and all the variables

-((-1N+10)/3)+3=0

We multiply all the terms by the denominator


-((-1N+10)+3*3)=0



We calculate terms in parentheses: -((-1N+10)+3*3), so:

(-1N+10)+3*3

We add all the numbers together, and all the variables

(-1N+10)+9

We get rid of parentheses

-1N+10+9

We add all the numbers together, and all the variables

-1N+19

Back to the equation:

-(-1N+19)



We get rid of parentheses

1N-19=0

We add all the numbers together, and all the variables

N-19=0

We move all terms containing N to the left, all other terms to the right

N=19

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