3(7x+3)=5x+41

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Solution for 3(7x+3)=5x+41 equation: 



3(7x+3)=5x+41

We move all terms to the left:

3(7x+3)-(5x+41)=0

We multiply parentheses

21x-(5x+41)+9=0

We get rid of parentheses

21x-5x-41+9=0

We add all the numbers together, and all the variables

16x-32=0

We move all terms containing x to the left, all other terms to the right

16x=32

x=32/16

x=2

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