3(7-z)-36=27z-5(3+6z)

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Solution for 3(7-z)-36=27z-5(3+6z) equation: 



3(7-z)-36=27z-5(3+6z)

We move all terms to the left:

3(7-z)-36-(27z-5(3+6z))=0

We add all the numbers together, and all the variables

3(-1z+7)-(27z-5(6z+3))-36=0

We multiply parentheses

-3z-(27z-5(6z+3))+21-36=0



We calculate terms in parentheses: -(27z-5(6z+3)), so:

27z-5(6z+3)

We multiply parentheses

27z-30z-15

We add all the numbers together, and all the variables

-3z-15

Back to the equation:

-(-3z-15)



We add all the numbers together, and all the variables

-3z-(-3z-15)-15=0

We get rid of parentheses

-3z+3z+15-15=0

We add all the numbers together, and all the variables

=0

z=0/1

z=0

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