3(7-c)-33=21c-4(3+6c)

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Solution for 3(7-c)-33=21c-4(3+6c) equation: 



3(7-c)-33=21c-4(3+6c)

We move all terms to the left:

3(7-c)-33-(21c-4(3+6c))=0

We add all the numbers together, and all the variables

3(-1c+7)-(21c-4(6c+3))-33=0

We multiply parentheses

-3c-(21c-4(6c+3))+21-33=0



We calculate terms in parentheses: -(21c-4(6c+3)), so:

21c-4(6c+3)

We multiply parentheses

21c-24c-12

We add all the numbers together, and all the variables

-3c-12

Back to the equation:

-(-3c-12)



We add all the numbers together, and all the variables

-3c-(-3c-12)-12=0

We get rid of parentheses

-3c+3c+12-12=0

We add all the numbers together, and all the variables

=0

c=0/1

c=0

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