y=6(2y-3)+14

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Solution for y=6(2y-3)+14 equation: 



y=6(2y-3)+14

We move all terms to the left:

y-(6(2y-3)+14)=0



We calculate terms in parentheses: -(6(2y-3)+14), so:

6(2y-3)+14

We multiply parentheses

12y-18+14

We add all the numbers together, and all the variables

12y-4

Back to the equation:

-(12y-4)



We get rid of parentheses

y-12y+4=0

We add all the numbers together, and all the variables

-11y+4=0

We move all terms containing y to the left, all other terms to the right

-11y=-4

y=-4/-11

y=4/11

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