3(7+2y)=30+7(y-1)

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Solution for 3(7+2y)=30+7(y-1) equation: 



3(7+2y)=30+7(y-1)

We move all terms to the left:

3(7+2y)-(30+7(y-1))=0

We add all the numbers together, and all the variables

3(2y+7)-(30+7(y-1))=0

We multiply parentheses

6y-(30+7(y-1))+21=0



We calculate terms in parentheses: -(30+7(y-1)), so:

30+7(y-1)

determiningTheFunctionDomain
7(y-1)+30

We multiply parentheses

7y-7+30

We add all the numbers together, and all the variables

7y+23

Back to the equation:

-(7y+23)



We get rid of parentheses

6y-7y-23+21=0

We add all the numbers together, and all the variables

-1y-2=0

We move all terms containing y to the left, all other terms to the right

-y=2

y=2/-1

y=-2

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