-(x+2)+3(5+x)=41

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Solution for -(x+2)+3(5+x)=41 equation: 



-(x+2)+3(5+x)=41

We move all terms to the left:

-(x+2)+3(5+x)-(41)=0

We add all the numbers together, and all the variables

-(x+2)+3(x+5)-41=0

We multiply parentheses

-(x+2)+3x+15-41=0

We get rid of parentheses

-x+3x-2+15-41=0

We add all the numbers together, and all the variables

2x-28=0

We move all terms containing x to the left, all other terms to the right

2x=28

x=28/2

x=14

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