3(6x+4)+2(4x+4)=3x+112

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Solution for 3(6x+4)+2(4x+4)=3x+112 equation: 



3(6x+4)+2(4x+4)=3x+112

We move all terms to the left:

3(6x+4)+2(4x+4)-(3x+112)=0

We multiply parentheses

18x+8x-(3x+112)+12+8=0

We get rid of parentheses

18x+8x-3x-112+12+8=0

We add all the numbers together, and all the variables

23x-92=0

We move all terms containing x to the left, all other terms to the right

23x=92

x=92/23

x=4

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