2(3x-2)+1=24+3(x-4)

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Solution for 2(3x-2)+1=24+3(x-4) equation: 



2(3x-2)+1=24+3(x-4)

We move all terms to the left:

2(3x-2)+1-(24+3(x-4))=0

We multiply parentheses

6x-(24+3(x-4))-4+1=0



We calculate terms in parentheses: -(24+3(x-4)), so:

24+3(x-4)

determiningTheFunctionDomain
3(x-4)+24

We multiply parentheses

3x-12+24

We add all the numbers together, and all the variables

3x+12

Back to the equation:

-(3x+12)



We add all the numbers together, and all the variables

6x-(3x+12)-3=0

We get rid of parentheses

6x-3x-12-3=0

We add all the numbers together, and all the variables

3x-15=0

We move all terms containing x to the left, all other terms to the right

3x=15

x=15/3

x=5

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