3(6t+1)-6=t-(t-2)

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Solution for 3(6t+1)-6=t-(t-2) equation: 



3(6t+1)-6=t-(t-2)

We move all terms to the left:

3(6t+1)-6-(t-(t-2))=0

We multiply parentheses

18t-(t-(t-2))+3-6=0



We calculate terms in parentheses: -(t-(t-2)), so:

t-(t-2)

We get rid of parentheses

t-t+2

We add all the numbers together, and all the variables

2

Back to the equation:

-(2)



We add all the numbers together, and all the variables

18t-5=0

We move all terms containing t to the left, all other terms to the right

18t=5

t=5/18

t=5/18

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