3(6r-5)2r=3(r-5)-5r

Solution for 3(6r-5)2r=3(r-5)-5r equation:

3(6r-5)2r=3(r-5)-5r

We move all terms to the left:

3(6r-5)2r-(3(r-5)-5r)=0

We multiply parentheses

36r^2-30r-(3(r-5)-5r)=0


We calculate terms in parentheses: -(3(r-5)-5r), so:

3(r-5)-5r

We add all the numbers together, and all the variables

-5r+3(r-5)

We multiply parentheses

-5r+3r-15

We add all the numbers together, and all the variables

-2r-15

Back to the equation:

-(-2r-15)


We get rid of parentheses

36r^2-30r+2r+15=0

We add all the numbers together, and all the variables

36r^2-28r+15=0

a = 36; b = -28; c = +15;
Δ = b2-4ac
Δ = -282-4·36·15
Δ = -1376
Delta is less than zero, so there is no solution for the equation