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7x-3=4+3/2x
We move all terms to the left:
7x-3-(4+3/2x)=0
Domain of the equation: 2x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
7x-(3/2x+4)-3=0
We get rid of parentheses
7x-3/2x-4-3=0
We multiply all the terms by the denominator
7x*2x-4*2x-3*2x-3=0
Wy multiply elements
14x^2-8x-6x-3=0
We add all the numbers together, and all the variables
14x^2-14x-3=0
a = 14; b = -14; c = -3;
Δ = b2-4ac
Δ = -142-4·14·(-3)
Δ = 364
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{364}=\sqrt{4*91}=\sqrt{4}*\sqrt{91}=2\sqrt{91}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-2\sqrt{91}}{2*14}=\frac{14-2\sqrt{91}}{28} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+2\sqrt{91}}{2*14}=\frac{14+2\sqrt{91}}{28} $
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