3(6f-7)=19+4f

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Solution for 3(6f-7)=19+4f equation: 



3(6f-7)=19+4f

We move all terms to the left:

3(6f-7)-(19+4f)=0

We add all the numbers together, and all the variables

3(6f-7)-(4f+19)=0

We multiply parentheses

18f-(4f+19)-21=0

We get rid of parentheses

18f-4f-19-21=0

We add all the numbers together, and all the variables

14f-40=0

We move all terms containing f to the left, all other terms to the right

14f=40

f=40/14

f=2+6/7

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