3(6-3z)=2z-10

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Solution for 3(6-3z)=2z-10 equation: 



3(6-3z)=2z-10

We move all terms to the left:

3(6-3z)-(2z-10)=0

We add all the numbers together, and all the variables

3(-3z+6)-(2z-10)=0

We multiply parentheses

-9z-(2z-10)+18=0

We get rid of parentheses

-9z-2z+10+18=0

We add all the numbers together, and all the variables

-11z+28=0

We move all terms containing z to the left, all other terms to the right

-11z=-28

z=-28/-11

z=2+6/11

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