3(6+2x)=8+(x-5)

Solution for 3(6+2x)=8+(x-5) equation:

3(6+2x)=8+(x-5)

We move all terms to the left:

3(6+2x)-(8+(x-5))=0

We add all the numbers together, and all the variables

3(2x+6)-(8+(x-5))=0

We multiply parentheses

6x-(8+(x-5))+18=0


We calculate terms in parentheses: -(8+(x-5)), so:

8+(x-5)

determiningTheFunctionDomain
(x-5)+8

We get rid of parentheses

x-5+8

We add all the numbers together, and all the variables

x+3

Back to the equation:

-(x+3)


We get rid of parentheses

6x-x-3+18=0

We add all the numbers together, and all the variables

5x+15=0

We move all terms containing x to the left, all other terms to the right

5x=-15

x=-15/5

x=-3