3(5z+7)+2(9z+11)=4(8z-13)-17

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Solution for 3(5z+7)+2(9z+11)=4(8z-13)-17 equation: 



3(5z+7)+2(9z+11)=4(8z-13)-17

We move all terms to the left:

3(5z+7)+2(9z+11)-(4(8z-13)-17)=0

We multiply parentheses

15z+18z-(4(8z-13)-17)+21+22=0



We calculate terms in parentheses: -(4(8z-13)-17), so:

4(8z-13)-17

We multiply parentheses

32z-52-17

We add all the numbers together, and all the variables

32z-69

Back to the equation:

-(32z-69)



We add all the numbers together, and all the variables

33z-(32z-69)+43=0

We get rid of parentheses

33z-32z+69+43=0

We add all the numbers together, and all the variables

z+112=0

We move all terms containing z to the left, all other terms to the right

z=-112

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