3(5z)+2(9z+11)=4(8z-13)-17

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Solution for 3(5z)+2(9z+11)=4(8z-13)-17 equation: 



3(5z)+2(9z+11)=4(8z-13)-17

We move all terms to the left:

3(5z)+2(9z+11)-(4(8z-13)-17)=0

We multiply parentheses

35z+18z-(4(8z-13)-17)+22=0



We calculate terms in parentheses: -(4(8z-13)-17), so:

4(8z-13)-17

We multiply parentheses

32z-52-17

We add all the numbers together, and all the variables

32z-69

Back to the equation:

-(32z-69)



We add all the numbers together, and all the variables

53z-(32z-69)+22=0

We get rid of parentheses

53z-32z+69+22=0

We add all the numbers together, and all the variables

21z+91=0

We move all terms containing z to the left, all other terms to the right

21z=-91

z=-91/21

z=-4+1/3

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