3(5z+24)+2=2(3-2z)-4

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Solution for 3(5z+24)+2=2(3-2z)-4 equation: 



3(5z+24)+2=2(3-2z)-4

We move all terms to the left:

3(5z+24)+2-(2(3-2z)-4)=0

We add all the numbers together, and all the variables

3(5z+24)-(2(-2z+3)-4)+2=0

We multiply parentheses

15z-(2(-2z+3)-4)+72+2=0



We calculate terms in parentheses: -(2(-2z+3)-4), so:

2(-2z+3)-4

We multiply parentheses

-4z+6-4

We add all the numbers together, and all the variables

-4z+2

Back to the equation:

-(-4z+2)



We add all the numbers together, and all the variables

15z-(-4z+2)+74=0

We get rid of parentheses

15z+4z-2+74=0

We add all the numbers together, and all the variables

19z+72=0

We move all terms containing z to the left, all other terms to the right

19z=-72

z=-72/19

z=-3+15/19

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