6(1+b)+3b=4

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Solution for 6(1+b)+3b=4 equation: 



6(1+b)+3b=4

We move all terms to the left:

6(1+b)+3b-(4)=0

We add all the numbers together, and all the variables

6(b+1)+3b-4=0

We add all the numbers together, and all the variables

3b+6(b+1)-4=0

We multiply parentheses

3b+6b+6-4=0

We add all the numbers together, and all the variables

9b+2=0

We move all terms containing b to the left, all other terms to the right

9b=-2

b=-2/9

b=-2/9

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