3(5f+2)-1f=2(f-3)

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Solution for 3(5f+2)-1f=2(f-3) equation: 



3(5f+2)-1f=2(f-3)

We move all terms to the left:

3(5f+2)-1f-(2(f-3))=0

We add all the numbers together, and all the variables

-1f+3(5f+2)-(2(f-3))=0

We multiply parentheses

-1f+15f-(2(f-3))+6=0



We calculate terms in parentheses: -(2(f-3)), so:

2(f-3)

We multiply parentheses

2f-6

Back to the equation:

-(2f-6)



We add all the numbers together, and all the variables

14f-(2f-6)+6=0

We get rid of parentheses

14f-2f+6+6=0

We add all the numbers together, and all the variables

12f+12=0

We move all terms containing f to the left, all other terms to the right

12f=-12

f=-12/12

f=-1

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