2c+2=2(3c-1)

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Solution for 2c+2=2(3c-1) equation: 



2c+2=2(3c-1)

We move all terms to the left:

2c+2-(2(3c-1))=0



We calculate terms in parentheses: -(2(3c-1)), so:

2(3c-1)

We multiply parentheses

6c-2

Back to the equation:

-(6c-2)



We get rid of parentheses

2c-6c+2+2=0

We add all the numbers together, and all the variables

-4c+4=0

We move all terms containing c to the left, all other terms to the right

-4c=-4

c=-4/-4

c=1

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