3(5-y)=7y-19

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Solution for 3(5-y)=7y-19 equation: 



3(5-y)=7y-19

We move all terms to the left:

3(5-y)-(7y-19)=0

We add all the numbers together, and all the variables

3(-1y+5)-(7y-19)=0

We multiply parentheses

-3y-(7y-19)+15=0

We get rid of parentheses

-3y-7y+19+15=0

We add all the numbers together, and all the variables

-10y+34=0

We move all terms containing y to the left, all other terms to the right

-10y=-34

y=-34/-10

y=3+2/5

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