3(5+x)=4(x+3)+15

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Solution for 3(5+x)=4(x+3)+15 equation: 



3(5+x)=4(x+3)+15

We move all terms to the left:

3(5+x)-(4(x+3)+15)=0

We add all the numbers together, and all the variables

3(x+5)-(4(x+3)+15)=0

We multiply parentheses

3x-(4(x+3)+15)+15=0



We calculate terms in parentheses: -(4(x+3)+15), so:

4(x+3)+15

We multiply parentheses

4x+12+15

We add all the numbers together, and all the variables

4x+27

Back to the equation:

-(4x+27)



We get rid of parentheses

3x-4x-27+15=0

We add all the numbers together, and all the variables

-1x-12=0

We move all terms containing x to the left, all other terms to the right

-x=12

x=12/-1

x=-12

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