3(5+x)+x+8=7(2x+3)+(x+2)

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Solution for 3(5+x)+x+8=7(2x+3)+(x+2) equation: 



3(5+x)+x+8=7(2x+3)+(x+2)

We move all terms to the left:

3(5+x)+x+8-(7(2x+3)+(x+2))=0

We add all the numbers together, and all the variables

3(x+5)+x-(7(2x+3)+(x+2))+8=0

We add all the numbers together, and all the variables

x+3(x+5)-(7(2x+3)+(x+2))+8=0

We multiply parentheses

x+3x-(7(2x+3)+(x+2))+15+8=0



We calculate terms in parentheses: -(7(2x+3)+(x+2)), so:

7(2x+3)+(x+2)

We multiply parentheses

14x+(x+2)+21

We get rid of parentheses

14x+x+2+21

We add all the numbers together, and all the variables

15x+23

Back to the equation:

-(15x+23)



We add all the numbers together, and all the variables

4x-(15x+23)+23=0

We get rid of parentheses

4x-15x-23+23=0

We add all the numbers together, and all the variables

-11x=0

x=0/-11

x=0

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