3(4z-2)=2(z+27)

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Solution for 3(4z-2)=2(z+27) equation: 



3(4z-2)=2(z+27)

We move all terms to the left:

3(4z-2)-(2(z+27))=0

We multiply parentheses

12z-(2(z+27))-6=0



We calculate terms in parentheses: -(2(z+27)), so:

2(z+27)

We multiply parentheses

2z+54

Back to the equation:

-(2z+54)



We get rid of parentheses

12z-2z-54-6=0

We add all the numbers together, and all the variables

10z-60=0

We move all terms containing z to the left, all other terms to the right

10z=60

z=60/10

z=6

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