3(4y+3)+2=71

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Solution for 3(4y+3)+2=71 equation: 



3(4y+3)+2=71

We move all terms to the left:

3(4y+3)+2-(71)=0

We add all the numbers together, and all the variables

3(4y+3)-69=0

We multiply parentheses

12y+9-69=0

We add all the numbers together, and all the variables

12y-60=0

We move all terms containing y to the left, all other terms to the right

12y=60

y=60/12

y=5

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