X2+3(x-1)=15

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Solution for X2+3(x-1)=15 equation:



X2+3(X-1)=15
We move all terms to the left:
X2+3(X-1)-(15)=0
We add all the numbers together, and all the variables
X^2+3(X-1)-15=0
We multiply parentheses
X^2+3X-3-15=0
We add all the numbers together, and all the variables
X^2+3X-18=0
a = 1; b = 3; c = -18;
Δ = b2-4ac
Δ = 32-4·1·(-18)
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-9}{2*1}=\frac{-12}{2} =-6 $
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+9}{2*1}=\frac{6}{2} =3 $

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