3(4y+2)=2(1+3y)+8

Solution for 3(4y+2)=2(1+3y)+8 equation:

3(4y+2)=2(1+3y)+8

We move all terms to the left:

3(4y+2)-(2(1+3y)+8)=0

We add all the numbers together, and all the variables

3(4y+2)-(2(3y+1)+8)=0

We multiply parentheses

12y-(2(3y+1)+8)+6=0


We calculate terms in parentheses: -(2(3y+1)+8), so:

2(3y+1)+8

We multiply parentheses

6y+2+8

We add all the numbers together, and all the variables

6y+10

Back to the equation:

-(6y+10)


We get rid of parentheses

12y-6y-10+6=0

We add all the numbers together, and all the variables

6y-4=0

We move all terms containing y to the left, all other terms to the right

6y=4

y=4/6

y=2/3