3(4x-6)=-18+12x

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Solution for 3(4x-6)=-18+12x equation: 



3(4x-6)=-18+12x

We move all terms to the left:

3(4x-6)-(-18+12x)=0

We add all the numbers together, and all the variables

3(4x-6)-(12x-18)=0

We multiply parentheses

12x-(12x-18)-18=0

We get rid of parentheses

12x-12x+18-18=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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