6(3x+4)-18+1=2(9x+3)+1

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Solution for 6(3x+4)-18+1=2(9x+3)+1 equation: 



6(3x+4)-18+1=2(9x+3)+1

We move all terms to the left:

6(3x+4)-18+1-(2(9x+3)+1)=0

We add all the numbers together, and all the variables

6(3x+4)-(2(9x+3)+1)-17=0

We multiply parentheses

18x-(2(9x+3)+1)+24-17=0



We calculate terms in parentheses: -(2(9x+3)+1), so:

2(9x+3)+1

We multiply parentheses

18x+6+1

We add all the numbers together, and all the variables

18x+7

Back to the equation:

-(18x+7)



We add all the numbers together, and all the variables

18x-(18x+7)+7=0

We get rid of parentheses

18x-18x-7+7=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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