3(4x-2)+7x=2(x-5)

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Solution for 3(4x-2)+7x=2(x-5) equation: 



3(4x-2)+7x=2(x-5)

We move all terms to the left:

3(4x-2)+7x-(2(x-5))=0

We add all the numbers together, and all the variables

7x+3(4x-2)-(2(x-5))=0

We multiply parentheses

7x+12x-(2(x-5))-6=0



We calculate terms in parentheses: -(2(x-5)), so:

2(x-5)

We multiply parentheses

2x-10

Back to the equation:

-(2x-10)



We add all the numbers together, and all the variables

19x-(2x-10)-6=0

We get rid of parentheses

19x-2x+10-6=0

We add all the numbers together, and all the variables

17x+4=0

We move all terms containing x to the left, all other terms to the right

17x=-4

x=-4/17

x=-4/17

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