35=-6(1-3x)-5(1-x)

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Solution for 35=-6(1-3x)-5(1-x) equation: 



35=-6(1-3x)-5(1-x)

We move all terms to the left:

35-(-6(1-3x)-5(1-x))=0

We add all the numbers together, and all the variables

-(-6(-3x+1)-5(-1x+1))+35=0



We calculate terms in parentheses: -(-6(-3x+1)-5(-1x+1)), so:

-6(-3x+1)-5(-1x+1)

We multiply parentheses

18x+5x-6-5

We add all the numbers together, and all the variables

23x-11

Back to the equation:

-(23x-11)



We get rid of parentheses

-23x+11+35=0

We add all the numbers together, and all the variables

-23x+46=0

We move all terms containing x to the left, all other terms to the right

-23x=-46

x=-46/-23

x=+2

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