3(4x+3)-7=9x-1/2(-6x-2)

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Solution for 3(4x+3)-7=9x-1/2(-6x-2) equation: 



3(4x+3)-7=9x-1/2(-6x-2)

We move all terms to the left:

3(4x+3)-7-(9x-1/2(-6x-2))=0



Domain of the equation: 2(-6x-2))!=0

x∈R



We multiply parentheses

12x-(9x-1/2(-6x-2))+9-7=0

We multiply all the terms by the denominator


12x*2(-6x-2))-(9x+9*2(-6x-2))-7*2(-6x-1-2))=0

We add all the numbers together, and all the variables

12x*2(-6x-2))-(9x+9*2(-6x-2))-7*2(-6x-3))=0

We add all the numbers together, and all the variables

-6x+12x*2(-6x-2))-(9x+9*2(-6x-2))-7*2(=0

Wy multiply elements

24x^2(-+36x^2(--6x=0

We use the square of the difference formula

24x^2(-36x^2(+6x=0

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