4(m-5)=4(m+4)+3m

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Solution for 4(m-5)=4(m+4)+3m equation: 



4(m-5)=4(m+4)+3m

We move all terms to the left:

4(m-5)-(4(m+4)+3m)=0

We multiply parentheses

4m-(4(m+4)+3m)-20=0



We calculate terms in parentheses: -(4(m+4)+3m), so:

4(m+4)+3m

We add all the numbers together, and all the variables

3m+4(m+4)

We multiply parentheses

3m+4m+16

We add all the numbers together, and all the variables

7m+16

Back to the equation:

-(7m+16)



We get rid of parentheses

4m-7m-16-20=0

We add all the numbers together, and all the variables

-3m-36=0

We move all terms containing m to the left, all other terms to the right

-3m=36

m=36/-3

m=-12

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