3(4x+3)-4(6x+1)=41

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Solution for 3(4x+3)-4(6x+1)=41 equation: 



3(4x+3)-4(6x+1)=41

We move all terms to the left:

3(4x+3)-4(6x+1)-(41)=0

We multiply parentheses

12x-24x+9-4-41=0

We add all the numbers together, and all the variables

-12x-36=0

We move all terms containing x to the left, all other terms to the right

-12x=36

x=36/-12

x=-3

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