3(4x+3)-4(6+1)=41

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Solution for 3(4x+3)-4(6+1)=41 equation: 



3(4x+3)-4(6+1)=41

We move all terms to the left:

3(4x+3)-4(6+1)-(41)=0

determiningTheFunctionDomain
3(4x+3)-41-4(6+1)=0

We add all the numbers together, and all the variables

3(4x+3)-41-47=0

We add all the numbers together, and all the variables

3(4x+3)-88=0

We multiply parentheses

12x+9-88=0

We add all the numbers together, and all the variables

12x-79=0

We move all terms containing x to the left, all other terms to the right

12x=79

x=79/12

x=6+7/12

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