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3(4x+1)-(4x-1)=2(x+5)
We move all terms to the left:
3(4x+1)-(4x-1)-(2(x+5))=0
We multiply parentheses
12x-(4x-1)-(2(x+5))+3=0
We get rid of parentheses
12x-4x-(2(x+5))+1+3=0
We calculate terms in parentheses: -(2(x+5)), so:We add all the numbers together, and all the variables
2(x+5)
We multiply parentheses
2x+10
Back to the equation:
-(2x+10)
8x-(2x+10)+4=0
We get rid of parentheses
8x-2x-10+4=0
We add all the numbers together, and all the variables
6x-6=0
We move all terms containing x to the left, all other terms to the right
6x=6
x=6/6
x=1
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