3(4g+2)-4(8-g)-10g=3(g+10)-(g+6)

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Solution for 3(4g+2)-4(8-g)-10g=3(g+10)-(g+6) equation: 



3(4g+2)-4(8-g)-10g=3(g+10)-(g+6)

We move all terms to the left:

3(4g+2)-4(8-g)-10g-(3(g+10)-(g+6))=0

We add all the numbers together, and all the variables

3(4g+2)-4(-1g+8)-10g-(3(g+10)-(g+6))=0

We add all the numbers together, and all the variables

-10g+3(4g+2)-4(-1g+8)-(3(g+10)-(g+6))=0

We multiply parentheses

-10g+12g+4g-(3(g+10)-(g+6))+6-32=0



We calculate terms in parentheses: -(3(g+10)-(g+6)), so:

3(g+10)-(g+6)

We multiply parentheses

3g-(g+6)+30

We get rid of parentheses

3g-g-6+30

We add all the numbers together, and all the variables

2g+24

Back to the equation:

-(2g+24)



We add all the numbers together, and all the variables

6g-(2g+24)-26=0

We get rid of parentheses

6g-2g-24-26=0

We add all the numbers together, and all the variables

4g-50=0

We move all terms containing g to the left, all other terms to the right

4g=50

g=50/4

g=12+1/2

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