3(4c-5)=6(4c+7)

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Solution for 3(4c-5)=6(4c+7) equation: 



3(4c-5)=6(4c+7)

We move all terms to the left:

3(4c-5)-(6(4c+7))=0

We multiply parentheses

12c-(6(4c+7))-15=0



We calculate terms in parentheses: -(6(4c+7)), so:

6(4c+7)

We multiply parentheses

24c+42

Back to the equation:

-(24c+42)



We get rid of parentheses

12c-24c-42-15=0

We add all the numbers together, and all the variables

-12c-57=0

We move all terms containing c to the left, all other terms to the right

-12c=57

c=57/-12

c=-4+3/4

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