3(4c-1)-6=7c+6

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Solution for 3(4c-1)-6=7c+6 equation: 



3(4c-1)-6=7c+6

We move all terms to the left:

3(4c-1)-6-(7c+6)=0

We multiply parentheses

12c-(7c+6)-3-6=0

We get rid of parentheses

12c-7c-6-3-6=0

We add all the numbers together, and all the variables

5c-15=0

We move all terms containing c to the left, all other terms to the right

5c=15

c=15/5

c=3

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