1/4(4x+16)=2(2x-1)

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Solution for 1/4(4x+16)=2(2x-1) equation:



1/4(4x+16)=2(2x-1)
We move all terms to the left:
1/4(4x+16)-(2(2x-1))=0
Domain of the equation: 4(4x+16)!=0
x∈R
We multiply all the terms by the denominator
-((2(2x-1)))*4(4x+16)+1=0
We calculate terms in parentheses: -((2(2x-1)))*4(4x+16), so:
(2(2x-1)))*4(4x+16
We calculate terms in parentheses: -((2(2x-1)))*4(4x+16), so:
(2(2x-1)))*4(4x+16
We calculate terms in parentheses: -((2(2x-1)))*4(4x+16), so:
(2(2x-1)))*4(4x+16
We calculate terms in parentheses: -((2(2x-1)))*4(4x+16), so:
(2(2x-1)))*4(4x+16
We calculate terms in parentheses: -((2(2x-1)))*4(4x+16), so:
(2(2x-1)))*4(4x+16
We calculate terms in parentheses: -((2(2x-1)))*4(4x+16), so:
(2(2x-1)))*4(4x+16
We calculate terms in parentheses: -((2(2x-1)))*4(4x+16), so:
(2(2x-1)))*4(4x+16
We calculate terms in parentheses: -((2(2x-1)))*4(4x+16), so:
(2(2x-1)))*4(4x+16
We calculate terms in parentheses: -((2(2x-1)))*4(4x+16), so:
(2(2x-1)))*4(4x+16
We calculate terms in parentheses: -((2(2x-1)))*4(4x+16), so:
(2(2x-1)))*4(4x+16
We calculate terms in parentheses: -((2(2x-1)))*4(4x+16), so:
(2(2x-1)))*4(4x+16
We calculate terms in parentheses: -((2(2x-1)))*4(4x+16), so:
(2(2x-1)))*4(4x+16
We calculate terms in parentheses: -((2(2x-1)))*4(4x+16), so:
(2(2x-1)))*4(4x+16
We calculate terms in parentheses: -((2(2x-1)))*4(4x+16), so:
(2(2x-1)))*4(4x+16
We calculate terms in parentheses: -((2(2x-1)))*4(4x+16), so:
(2(2x-1)))*4(4x+16
We calculate terms in parentheses: -((2(2x-1)))*4(4x+16), so:
(2(2x-1)))*4(4x+16
We calculate terms in parentheses: -((2(2x-1)))*4(4x+16), so:
(2(2x-1)))*4(4x+16
We calculate terms in parentheses: -((2(2x-1)))*4(4x+16), so:
(2(2x-1)))*4(4x+16
We calculate terms in parentheses: -((2(2x-1)))*4(4x+16), so:
(2(2x-1)))*4(4x+16
We calculate terms in parentheses: -((2(2x-1)))*4(4x+16), so:
(2(2x-1)))*4(4x+16
We calculate terms in parentheses: -((2(2x-1)))*4(4x+16), so:
(2(2x-1)))*4(4x+16
We calculate terms in parentheses: -((2(2x-1)))*4(4x+16), so:
(2(2x-1)))*4(4x+16
We calculate terms in parentheses: -((2(2x-1)))*4(4x+16), so:
(2(2x-1)))*4(4x+16
We calculate terms in parentheses: -((2(2x-1)))*4(4x+16), so:
(2(2x-1)))*4(4x+16
We calculate terms in parentheses: -((2(2x-1)))*4(4x+16), so:
(2(2x-1)))*4(4x+16
We calculate terms in parentheses: -((2(2x-1)))*4(4x+16), so:
(2(2x-1)))*4(4x+16
We calculate terms in parentheses: -((2(2x-1)))*4(4x+16), so:
(2(2x-1)))*4(4x+16
We calculate terms in parentheses: -((2(2x-1)))*4(4x+16), so:
(2(2x-1)))*4(4x+16
We calculate terms in parentheses: -((2(2x-1)))*4(4x+16), so:
(2(2x-1)))*4(4x+16
We calculate terms in parentheses: -((2(2x-1)))*4(4x+16), so:
(2(2x-1)))*4(4x+16
We calculate terms in parentheses: -((2(2x-1)))*4(4x+16), so:
(2(2x-1)))*4(4x+16
We calculate terms in parentheses: -((2(2x-1)))*4(4x+16), so:
(2(2x-1)))*4(4x+16
We calculate terms in parentheses: -((2(2x-1)))*4(4x+16), so:
(2(2x-1)))*4(4x+16
We calculate terms in parentheses: -((2(2x-1)))*4(4x+16), so:
(2(2x-1)))*4(4x+16
We calculate terms in parentheses: -((2(2x-1)))*4(4x+16), so:
(2(2x-1)))*4(4x+16
We calculate terms in parentheses: -((2(2x-1)))*4(4x+16), so:
(2(2x-1)))*4(4x+16
We calculate terms in parentheses: -((2(2x-1)))*4(4x+16), so:
(2(2x-1)))*4(4x+16
We calculate terms in parentheses: -((2(2x-1)))*4(4x+16), so:
(2(2x-1)))*4(4x+16
We calculate terms in parentheses: -((2(2x-1)))*4(4x+16), so:
(2(2x-1)))*4(4x+16
We calculate terms in parentheses: -((2(2x-1)))*4(4x+16), so:
(2(2x-1)))*4(4x+16
We calculate terms in parentheses: -((2(2x-1)))*4(4x+16), so:
(2(2x-1)))*4(4x+16
We calculate terms in parentheses: -((2(2x-1)))*4(4x+16), so:
(2(2x-1)))*4(4x+16
We calculate terms in parentheses: -((2(2x-1)))

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