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3(4b-6)=3-(3b-9)
We move all terms to the left:
3(4b-6)-(3-(3b-9))=0
We multiply parentheses
12b-(3-(3b-9))-18=0
We calculate terms in parentheses: -(3-(3b-9)), so:We get rid of parentheses
3-(3b-9)
determiningTheFunctionDomain -(3b-9)+3
We get rid of parentheses
-3b+9+3
We add all the numbers together, and all the variables
-3b+12
Back to the equation:
-(-3b+12)
12b+3b-12-18=0
We add all the numbers together, and all the variables
15b-30=0
We move all terms containing b to the left, all other terms to the right
15b=30
b=30/15
b=2
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