(x)+(2x)+(x+3)+(2x-2)+(2x+1)=58

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Solution for (x)+(2x)+(x+3)+(2x-2)+(2x+1)=58 equation: 



(x)+(2x)+(x+3)+(2x-2)+(2x+1)=58

We move all terms to the left:

(x)+(2x)+(x+3)+(2x-2)+(2x+1)-(58)=0

We add all the numbers together, and all the variables

3x+(x+3)+(2x-2)+(2x+1)-58=0

We get rid of parentheses

3x+x+2x+2x+3-2+1-58=0

We add all the numbers together, and all the variables

8x-56=0

We move all terms containing x to the left, all other terms to the right

8x=56

x=56/8

x=7

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