3(4-x)+6x)=4x+12-x

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Solution for 3(4-x)+6x)=4x+12-x equation: 



3(4-x)+6x)=4x+12-x

We move all terms to the left:

3(4-x)+6x)-(4x+12-x)=0

We add all the numbers together, and all the variables

3(-1x+4)+6x)-(+3x)+12=0

We multiply parentheses

-3x+6x)-(+3x)+12+12=0

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