3(4-2x)=12-20x+4x

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Solution for 3(4-2x)=12-20x+4x equation: 



3(4-2x)=12-20x+4x

We move all terms to the left:

3(4-2x)-(12-20x+4x)=0

We add all the numbers together, and all the variables

3(-2x+4)-(-16x+12)=0

We multiply parentheses

-6x-(-16x+12)+12=0

We get rid of parentheses

-6x+16x-12+12=0

We add all the numbers together, and all the variables

10x=0

x=0/10

x=0

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