3(x+2)+3(2x+2=48

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Solution for 3(x+2)+3(2x+2=48 equation: 



3(x+2)+3(2x+2=48

We move all terms to the left:

3(x+2)+3(2x+2-(48)=0

We multiply parentheses

3x+3(2x+2-48+6=0

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