3(4-2x)-18=6-2(x-3)

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Solution for 3(4-2x)-18=6-2(x-3) equation: 



3(4-2x)-18=6-2(x-3)

We move all terms to the left:

3(4-2x)-18-(6-2(x-3))=0

We add all the numbers together, and all the variables

3(-2x+4)-(6-2(x-3))-18=0

We multiply parentheses

-6x-(6-2(x-3))+12-18=0



We calculate terms in parentheses: -(6-2(x-3)), so:

6-2(x-3)

determiningTheFunctionDomain
-2(x-3)+6

We multiply parentheses

-2x+6+6

We add all the numbers together, and all the variables

-2x+12

Back to the equation:

-(-2x+12)



We add all the numbers together, and all the variables

-6x-(-2x+12)-6=0

We get rid of parentheses

-6x+2x-12-6=0

We add all the numbers together, and all the variables

-4x-18=0

We move all terms containing x to the left, all other terms to the right

-4x=18

x=18/-4

x=-4+1/2

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