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3(4+x)=10(2+x)
We move all terms to the left:
3(4+x)-(10(2+x))=0
We add all the numbers together, and all the variables
3(x+4)-(10(x+2))=0
We multiply parentheses
3x-(10(x+2))+12=0
We calculate terms in parentheses: -(10(x+2)), so:We get rid of parentheses
10(x+2)
We multiply parentheses
10x+20
Back to the equation:
-(10x+20)
3x-10x-20+12=0
We add all the numbers together, and all the variables
-7x-8=0
We move all terms containing x to the left, all other terms to the right
-7x=8
x=8/-7
x=-1+1/7
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