10x+40(0.2)=80

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Solution for 10x+40(0.2)=80 equation: 



10x+40(0.2)=80

We move all terms to the left:

10x+40(0.2)-(80)=0

determiningTheFunctionDomain
10x-80+40(0.2)=0

We add all the numbers together, and all the variables

10x-72=0

We move all terms containing x to the left, all other terms to the right

10x=72

x=72/10

x=7+1/5

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