3(4+n)=2(n-5)

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Solution for 3(4+n)=2(n-5) equation:


Simplifying
3(4 + n) = 2(n + -5)
(4 * 3 + n * 3) = 2(n + -5)
(12 + 3n) = 2(n + -5)

Reorder the terms:
12 + 3n = 2(-5 + n)
12 + 3n = (-5 * 2 + n * 2)
12 + 3n = (-10 + 2n)

Solving
12 + 3n = -10 + 2n

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-2n' to each side of the equation.
12 + 3n + -2n = -10 + 2n + -2n

Combine like terms: 3n + -2n = 1n
12 + 1n = -10 + 2n + -2n

Combine like terms: 2n + -2n = 0
12 + 1n = -10 + 0
12 + 1n = -10

Add '-12' to each side of the equation.
12 + -12 + 1n = -10 + -12

Combine like terms: 12 + -12 = 0
0 + 1n = -10 + -12
1n = -10 + -12

Combine like terms: -10 + -12 = -22
1n = -22

Divide each side by '1'.
n = -22

Simplifying
n = -22

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